112=3x^2+4

Solution for 112=3x^2+4 equation:

112=3x^2+4

We move all terms to the left:

112-(3x^2+4)=0

We get rid of parentheses

-3x^2-4+112=0

We add all the numbers together, and all the variables

-3x^2+108=0

a = -3; b = 0; c = +108;
Δ = b2-4ac
Δ = 02-4·(-3)·108
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-3}=\frac{-36}{-6}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-3}=\frac{36}{-6}
=-6
$